x^2-228x+2996=0

Solution for x^2-228x+2996=0 equation:

x^2-228x+2996=0

a = 1; b = -228; c = +2996;
Δ = b2-4ac
Δ = -2282-4·1·2996
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-228)-200}{2*1}=\frac{28}{2}
=14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-228)+200}{2*1}=\frac{428}{2}
=214
$